Thread: Arithmetic Series
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Old May 2nd, 2008, 12:02 AM
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Originally Posted by Mathstud28 View Post
\sum_{n=0}^{x}2n+1=\sum_{n=0}^{x}2n+\sum_{n=0}^{x}1=\frac{2x(x+1)}{2}+x{\color{red}+1}
There are n-p+1 elements in the set of positive integers \{p,\,p+1,\,p+2,\,\ldots,\,n-1,\,n\}, assuming n\geq p.
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