Thread: [SOLVED] Quadratic Equation
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Old May 2nd, 2008, 06:53 AM
zp3929 zp3929 is offline
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Quote:
Originally Posted by looi76 View Post
Question:
Find the value of x when y = 0
y = \frac{2x - 1}{x + 3}
this is what i did (dont know if it is right or not though)
y = \frac{2x - 1}{x + 3}

{2x - 1}= 0

{2x} = 1

{x} = 1/2

Zac
Last edited by zp3929; May 2nd, 2008 at 07:08 AM.
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