Thread: [SOLVED] Quadratic Equation
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Old May 2nd, 2008, 06:55 AM
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Quote:
Originally Posted by zp3929 View Post
this is what i did (dont know if it is right or not though)
y = \frac{2x - 1}{x + 3}

{x + 3} = {2x - 1}

{-x + 4} = 0

{-x} = -4

{x} = 4

Zac
What you did was for y=1
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