Thread: [SOLVED] Quadratic Equation
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Old May 2nd, 2008, 07:00 AM
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Quote:
Originally Posted by zp3929 View Post
this is what i did (dont know if it is right or not though)
y = \frac{2x - 1}{x + 3}

{-x - 3} = {2x - 1}

{-3x -2} = 0

{-3x} = 2

{x} = -2/3

Zac
Now, this is for y=-1
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