Math Help Forum - View Single Post - [SOLVED] Quadratic Equation

Quote:

Originally Posted by zp3929

this is what i did (dont know if it is right or not though)
$y = \frac{2x - 1}{x + 3}$

${2x - 1}= 0$

${2x} = 1$

${x} = 1/2$

Zac

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