Thread: [SOLVED] Quadratic Equation
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Old May 2nd, 2008, 07:12 AM
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y = \frac{2x - 1}{x + 3}

y = 0

\frac{2x - 1}{x + 3} = 0

2x - 1 = x + 3
2x - 1 - x - 3 = 0
x - 4 = 0
x = 4

The answer I have is x = \frac{1}{2} ?!
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