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zp3929 · #11 May 2nd, 2008, 07:15 AM

Quote:

Originally Posted by looi76

$y = \frac{2x - 1}{x + 3}$

$y = 0$

$\frac{2x - 1}{x + 3} = 0$

$2x - 1 = x + 3$
$2x - 1 - x - 3 = 0$
$x - 4 = 0$
$x = 4$

The answer I have is $x = \frac{1}{2}$ ?!

yer it is $x = \frac{1}{2}$
i edited my post (several times

)

we get rid of the $x = 3$ because $x = 3$ /0 = 0 which leaves us with $2x - 1 = 0$

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looi76
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