Thread: algebra
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Old May 2nd, 2008, 02:35 PM
icemanfan icemanfan is offline
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Quote:
Originally Posted by gumi View Post
Polynomial p(x) and a divisor d(x) are given. Find the quotient q(x) and the remainder r(x) when p(x) is divided by d(x).


a,
p(x)=12x^3-40x^2+11x+39
d(x)=2x-5




b,
p(x)=x^4+x^2+2
d(x)=x^2+x+1
This is just long division of polynomials. I'll walk you through the first one.
We need to find the correct multiple of 2x - 5 to get to the level of 12x^3. That multiple is 6x^2.

So we multiply 6x^2 \cdot (2x-5) = 12x^2 - 30x^2 and subtract that from 12x^3 - 40x^2 + 11x + 39, which leaves us with -10x^2 + 11x + 39. Now, how many times will 2x - 5 go into this? -5x.

So -5x \cdot (2x - 5) = -10x^2 + 25x and we subtract out -10x^2 + 25x, leaving us with -14x + 39. Finally, we see that we need a multiple of -7 for the last step:

-7(2x - 5) = -14x + 35 and we subtract this from -14x + 39 to yield 4.

The answer is therefore:

q(x) = 6x^2 - 5x - 7

r(x) = \frac{4}{2x - 5}
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