Thread: Two Integrals
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Old May 11th, 2008, 05:32 PM
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TheEmptySet TheEmptySet is offline
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Originally Posted by Hibijibi View Post
How did you know to divide there? Just by practice? Other problems similar to those I've seen them split up and then several u's are used. I'm assuming you did that since the top and bottom powers were equal??
As a general rule if the degree of the numerator is greater than or equal to the denominator divide.

I also want to point out this trick (I forget it alot), but when they have the same degree like yours this can be done.

\frac{x-1}{x+1}=\frac{(x+1)-2}{x+1}=\frac{x+1}{x+1}+\frac{-2}{x+1}=1-\frac{2}{x+1}
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