Thread: interest problems
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Old May 14th, 2008, 04:27 PM
Soroban Soroban is offline
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Hello, mandy!

Quote:
James is buying a house on a 30-year conventional mortgage at 6.25% APR.
He will put 3% down on the loan.
If he wants to keep his monthly payments at or below $1,000,
how much is the most expensive house James can buy?

The amortization formula is: .P \;=\;A\,\frac{(1+i)^n - 1}{i(1+i)^n}

. . where: .\begin{Bmatrix}P &=& \text{principal amount of the loan} \\ A &=& \text{periodic payment} \\ i &=& \text{periodic interest rate} \\ n &=&\text{number of periods} \end{Bmatrix}


We have: .A = 1000,\;i = \frac{0.0625}{12},\;n = 360

Then: .P \;=\;1000\,\frac{\left(1+\frac{0.0625}{12}\right)^{360}-1}{\frac{0.0625}{12}\left(1 + \frac{0.0625}{12}\right)^{360}} \;\approx\; \$162,412.22

This is the maximum amount he can borrow,
. . which is 97% of the price of the house.


Therefore, he can buy a house up to: .\frac{\$162,412.22}{0.97} \;\approx\;\$167,435.28
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