Thread: geometry help
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Old May 19th, 2008, 05:31 PM
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Quote:
Originally Posted by Mathstud28 View Post
A general desire for the underyling is never hurtful

usign my formula \frac{5}{4}\cdot{b^2}\cdot\cot\bigg(\frac{\pi}{5}\bigg)=\frac{10(\sqrt{5}+1)\sqrt{2}x^2}{\sqrt{5-\sqrt{5}}}\approx{27.52b^2}

So now apply it

plug in your b value

and use the fact that

A=\frac{1}{2}p\cdot{a}

to find the apothem
I am so sorry, but that math looks like a foreign language to me. Can you go a little slower with it please?
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