Thread: solve equation
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Old May 21st, 2008, 03:51 PM
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Quote:
Originally Posted by nasb View Post
2-Solve:

a: 8x-7=5(x+4)
b: 8-2x=5
c: 3x-5=7
d: 7(3-p)=9-4p
These are all of the same type.
8x - 7  =5(x + 4)

8x - 7 = 5 \cdot x + 5 \cdot 4

8x - 7 = 5x + 20

8x - 7 - 5x = 5x + 20 - 5x

3x - 7 = 20

3x - 7 + 7 = 20 + 7

3x = 27

\frac{3x}{3} = \frac{27}{3}

x = 9

The other three use the same basic pattern of solution. Try them again, step by step, using the above solution as a model. If you are still stuck on any of them, just let us know.

-Dan
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