Thread: Disguised quadratic equations
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Old May 22nd, 2008, 10:26 AM
sean.1986 sean.1986 is offline
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Quote:
Originally Posted by Mouseman View Post
I'm having troubles solving the following problem.

x^6 + 5x^3 -24 = 0

Please post solution.

Thanks in advance

Mouseman
(x^3 + 8)(x^3 - 3) = 0

x = cubert(-8) or x = cubert(3)
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