Thread: Algebra with pq-formula
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Old May 22nd, 2008, 12:26 PM
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Originally Posted by liljeros View Post
a) Show that if an Quadratic equation has the roots x_{1}=a x_{2}=b then the equation is x^2-(a+b)x+ab=0

b) Solve the Equation above and show that is has the solutions x_{1}=a x_{2}=b

I am quite sure that you need to use the pq-formula for this one but then you get x=\frac{(a+b)}{2} \pm \sqrt{-(\frac{(a+b)}{2})^2}-ab
If you continue with your "pq" formula, you will arrive at the same conclusion; that x_1=a \ and \ x_2=b

This is a much longer process, but if that's the way you have to do it, then just continue with what you already started.
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