View Single Post
  #8  
Old May 22nd, 2008, 11:57 AM
liljeros liljeros is offline
Newbie
 
Join Date: Jan 2008
Posts: 15
Country:
Thanks: 11
Thanked 0 Times in 0 Posts
liljeros is on a distinguished road
Default

Quote:
Originally Posted by masters View Post
x=\frac{a+b}{2}\pm\sqrt{(\frac{a+b}{2})^2-ab}
---------------------------------------------------------------
x_1=\frac{a+b}{2} + \sqrt{\frac{a^2+2ab+b^2}{4}}-ab

x_1=\frac{a+b}{2}+\sqrt{\frac{a^2+2ab+b^2}{4}}-\frac{4ab}{4}

x_1=\frac{a+b}{2}+\sqrt{\frac{a^2+2ab+b^2-4ab}{4}}

x_1=\frac{a+b}{2}+\sqrt{\frac{a^2-2ab+b^2}{4}}

x_1=\frac{a+b}{2}+\frac{a-b}{2}

x_1=\frac{a+b+a-b}{2}

x_1=\frac{2a}{2}

x_1=a

Now, perform a similar task to find x_2
You really are the master! A friend to me explained the thing you were talking about before and it seems like I have learnd that and it helped me alot! Thank you *2

Very kind of you to help me out!
Reply With Quote