Thread: solve equation
View Single Post
  #5  
Old May 22nd, 2008, 03:09 PM
nasb nasb is offline
Newbie
 
Join Date: Oct 2007
Posts: 14
Country:
Thanks: 6
Thanked 1 Time in 1 Post
nasb is on a distinguished road
Default

Quote:
Originally Posted by topsquark View Post
These are all of the same type.
8x - 7 =5(x + 4)

8x - 7 = 5 \cdot x + 5 \cdot 4

8x - 7 = 5x + 20

8x - 7 - 5x = 5x + 20 - 5x

3x - 7 = 20

3x - 7 + 7 = 20 + 7

3x = 27

\frac{3x}{3} = \frac{27}{3}

x = 9

The other three use the same basic pattern of solution. Try them again, step by step, using the above solution as a model. If you are still stuck on any of them, just let us know.

-Dan
can you give answers for more please?
Reply With Quote