Thread: number of pairs
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Old June 18th, 2008, 10:41 AM
Soroban Soroban is offline
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Hello, robkitch!

Your English is not quite readable . . .

Quote:
if u are dealt 5 cards what is the possible way of getting a pair which a pair can be a 2 and a 3
I'll take a guess at what you meant . . .


We want five cards: one Deuce, one Trey, and three Others.

To get one Deuce, there are: {4\choose1} = 4 ways.

To get one Trey, there are: {4\choose1} = 4 ways.

To get three Others, there are: {44\choose3} = 13,244 ways.


Therefore, there are: .4 \times 4 \times 13,244 \:=\:\boxed{211,904\text{ ways}}
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