Thread: 2^a 2^b == 2^b+3 (mod 9)
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Old June 19th, 2008, 07:24 PM
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Quote:
Originally Posted by sleepingcat View Post
2^{a+b}\equiv 2^b+3 \mod9
I did a case analysis on b mod 6 and found the congruences a has to satisfy, but I don't think my answer is right... Any good resources on modular arithmetic are appreciated also!
Let a=b=0 and then 1 \equiv 1 + 3 (\bmod 9) and this is not true.
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