Thread: the distance and midpoint formulas
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Old July 30th, 2008, 05:53 PM
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Quote:
Originally Posted by tutor View Post
here the given points are A(0,0) B(3,3) C(6,0)
Distance between AB=sqrt(9+9)=sqrt(18)
distance between Ac=sqrt(36)=6
Distance between BC=sqrt(9+9)=sqrt(18)
clearly here any two sides are equal which is isoscles of a traingle
Moreover, \left( {\sqrt {18} } \right)^2 + \left( {\sqrt {18} } \right)^2 = \left( 6 \right)^2
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