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Old August 11th, 2008, 07:49 AM
Dubulus Dubulus is offline
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Quote:
Originally Posted by Laura901 View Post
81 x ^10 y^6 divided by (3x^2 y) ^4

6x+18 over x plus 3


12c^2 divided by 3c +6
1. start by expanding the bottom...

3^4 * (x^2)^4 * y^4 =
81x^8y^4

now cancel like terms
the 81 is removed completely
x^10/x^8 = x^2
y^6/y^4 = y^2

final answer: x^2 * y^2
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