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Old August 25th, 2008, 04:44 AM
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Quote:
Originally Posted by Number Cruncher 20 View Post
Hi,

I have been asked to derive a simple closed form expression for the
following sum:

n
∑ (-1)^(m+i) *(nCi)*(iCm) = S n, m
i = m

[with m = 0,1,2,....,n ; n= 0,1,2,....] and C is the combinations symbol.


I know that we are meant to be using the binomial theorem but I dont quite know where to go from there. Any help would be much appreciated.
Three hints:

1. Prove that \sum_{i=0}^{n} (-1)^i {n \choose i} is equal to zero if n \neq 0 and is equal to 1 if n = 0.

2. Prove that {n \choose k} {k \choose l} = {n \choose l} {n - l \choose k - l} for l \leq k.

3. Deduce from 1. and 2. that your expression is equal to zero if m \neq n and is equal to 1 if n = m.
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