Thread: concentration problem
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Old October 3rd, 2008, 10:04 AM
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Let x=amount to be drained.

Original mixture less amount drained: (18-x)

Amount of pure antifreeze=.15(18-x)

plus

pure antifreeze is x quarts.

The new mixture is 40%= .4(18)=7.2

So, we have the equation to solve:

.15(18-x)+x=7.2
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