Quote:
Originally Posted by Amelia  is there ne way i could help on one more problem... it has to do with quarters, nickles, and dimes for some reason i cant get it:
I have a collection of nickels, dimes, and quarters
in a money bag worth $7.95. If the number of
quarters is one more than the number of nickels
and the number of dimes is five more than the number
of nickels, find the number of each type of coin.
# Nickels ________
# Dimes_________¬
# Quarters________ |
In future, please make a new thread for each new question.
Okay we have 3 different types of coins.
So:
x + y + z = 7,95
Nickels = x
Quarters = y = x + 1
Dimes = z = x + 5
So you'll just need to substitute the values of these coins. And solve.
a(x) + b(x + 1) + c(x + 5) = 7,95
Where a;b;c are the monetary values of nickels, dimes, and quarters (not respectively!). I don't know the American system.
__________________
If you need more than 3 levels of indentation, you're screwed anyway, and should fix your program. - Linus Torvalds
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