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Old October 3rd, 2008, 11:01 AM
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earboth earboth is offline
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Quote:
Originally Posted by Amelia View Post
is there ne way i could help on one more problem... it has to do with quarters, nickles, and dimes for some reason i cant get it:

I have a collection of nickels, dimes, and quarters
in a money bag worth $7.95. If the number of
quarters is one more than the number of nickels
and the number of dimes is five more than the number
of nickels, find the number of each type of coin.
# Nickels ________
# Dimes_________¬
# Quarters________
Probably this comes too late but I'll post it nevertheless:

Let x denote the number of nickel coins, then the value of these coins is 0.05x
Let x+1 denote the number of quarter coins, then the value of these coins is 0.25(x+1)
Let x+5 denote the number of dime coins, then the value of these coins is 0.1(x+5)

Sum up the values

0.05x+0.25(x+1)+0.1(x+5)=7.95

Expand the brackets, collect like terms and solve for x.

I've got x =18.
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