View Single Post
  #2  
Old October 4th, 2008, 09:13 AM
bkarpuz's Avatar
bkarpuz bkarpuz is offline
Senior Member
 
Join Date: Sep 2008
Location: R³
Posts: 321
Country:
Thanks: 80
Thanked 65 Times in 59 Posts
bkarpuz will become famous soon enoughbkarpuz will become famous soon enough
Send a message via ICQ to bkarpuz Send a message via AIM to bkarpuz Send a message via MSN to bkarpuz Send a message via Yahoo to bkarpuz Send a message via Skype™ to bkarpuz
Default

Quote:
Originally Posted by Jaffa View Post
Can somebody help me with this question,
From a piece of wire 5000mm long, n pieces are cut,each piece 10mm longer
than the previous piece. If u is the lenght of the i-th piece and Si is the
cumulative lenght of i pieces.

(i) Express Un and Sn in terms of Ui and n
(ii)Determine the number of pieces that can be cut if Ui is 155mm

Could you please explain the answer

thanks
I will show you some little about the solution.
(i) Let u(1) be the length of the first term.
Then, we have u(2)=u(1)+10, u(3)=u(2)+10=u(1)+20, and in general u(i)=u(i-1)+10=u(i-2)+20=\ldots=u(1)+(i-1)10 for i=2,3,\ldots,n.
And
S(i)=\sum\limits_{j=1}^{i}u(j)
.......=\sum\limits_{j=1}^{i}[u(1)+(j-1)10]
.......=u(1)\sum\limits_{j=1}^{i}1+10\sum\limits_{j=1}^{i}(j-1)
.......=iu(1)+10\frac{(i-1)i}{2}
.......=iu(1)+5(i-1)i
for i=1,2,\ldots,n.
(ii) I guess u(1)=155mm, just consider the arguments in (i), and solve n by setting S(n)=5000mm.
Reply With Quote