Thread: linear algebra- vector-basis-subspace
View Single Post
  #4  
Old October 10th, 2008, 06:05 PM
watchmath watchmath is offline
Junior Member
  
Join Date: Oct 2008
Posts: 61
Country:
Thanks: 0
Thanked 26 Times in 26 Posts
watchmath is on a distinguished road
Default
The two unit vectors (that you chose) might be not generators of the subspace even they generate a subspace of dimension 2.

You need to take 2 vectors among the 4 original vectors. Since you know that the subspace has dimension two you can take any two vectors (among 4) for which the two are linearly independent.
__________________
Watch Free Math Videos

To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.


To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.
Reply With Quote
The following users thank watchmath for this useful post:
Donate to MHF