Math Help Forum - View Single Post

magentarita · #3 October 16th, 2008, 07:12 PM

Quote:

Originally Posted by masters

See diagram.

Length of major axis = 2a = 112

a = 56

The distance from a focus to a y-intercept is also = a.

The distance from the center to a focus = c = 50.

The distance from the center to the y-intercept = b. This is what we want to find.

$b^2+c^2=a^2$

$b^2=56^2-50^2$

$b\approx25.2$ feet.

Another great reply!