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Erzenwald · #4 November 9th, 2008, 06:42 AM

I found a solution

$3*4^x - 6^x = 2*9^x$ We divide all by $2*9^x$

$\frac{3}{2}*\frac{{4^x }}{{9^x }} - \frac{1}{2}*\frac{{6^x }}{{9^x }} = 1$
We get the equation to a simpler form

$\frac{3}{2}*\frac{{2^{2x} }}{{3^{2x} }} - \frac{1}{2}*\frac{{3^x 2^x }}{{3^{2x} }} = 1$

$\frac{3}{2}*\frac{{2^{2x} }}{{3^{2x} }} - \frac{1}{2}*\frac{{2^x }}{{3^x }} = 1$

Now we can write

$\frac{{2^x }}{{3^x }}$ as Y and solve the quadratic equation

The Following 2 Users Say Thank You to Erzenwald For This Useful Post:
mr fantastic, Rapha
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