Thread: arithmetic progression
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Old November 10th, 2008, 05:13 AM
jvignacio jvignacio is offline
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Quote:
Originally Posted by mr fantastic View Post
You're expcted to know that t_n = t_1 + (n-1)d.

Therefore 5000 = 200 + (n - 1) 150.

Solve for n.

so the total number of terms within 200 & 5000 is 30 and the total sum = 71250?
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