Thread: arithmetic progression
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Old November 10th, 2008, 05:42 AM
HallsofIvy HallsofIvy is offline
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Originally Posted by jvignacio View Post
so the total number of terms within 200 & 5000 is 30 and the total sum = 71250?
From 200 to 5000 is a distance of 4800 and 4800/150= 32. Since that counts only the steps and not the first number in the sequence the number of terms is 33.
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