Math Help Forum - View Single Post

Markus123 · #1 November 14th, 2008, 06:43 PM

Hi,

Could somebody please tell me where I'm going wrong, or if it's the book that's wrong on this (easy) question:

$\frac{2^6}{8^{2\frac{1}{2}}*2^{-\frac{1}{2}}}$

I get:

$\frac{2^6}{(2^3)^{2\frac{1}{2}}*2^{-\frac{1}{2}}}$

$= \frac{2^6}{2^{7\frac{1}{2}}*2^{-\frac{1}{2}}}$

$= \frac{2^6}{2^7}$

$= 2^{-1}$

$= \frac{1}{2}$

The book however has the answer as:

$2^\frac{39}{4}$

I'm pretty sure I'm right because multiplying it out gives 0.5, but I tried it in an online solver and they come out with the same answer as the book.