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Old November 15th, 2008, 04:46 AM
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Firstly, we need to find the conversion factor (something like between Celcius <=> Fahrenheit relations):
300u-30u=1500-500
270u=1000
1u=\frac{100}{27}+X
increase of 1u is equal to increase of value \frac{100}{27} and it's obvious, that both scales start in different places, so we need to find the constant number, which will be added during conversion:
30u=500
30*\frac{100}{27}+X=500 \Rightarrow X=\frac{3500}{9}
we can treat it as a function: u(n)=\frac{100}{27}n+\frac{3500}{9}
and then: u(80)=\frac{100}{27}*80+\frac{3500}{9}=\frac{18500}{27}=688,(185)

Of course I assumed, that the units are linear to values, in reality, they might look different. I mean, that grafically our function is a linear function, which might be any other one as well. I hope you kow what I mean.
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