Thread: probability independent distribution
View Single Post
  #1  
Old November 17th, 2008, 07:37 AM
Number Cruncher 20 Number Cruncher 20 is offline
Newbie
  
Join Date: May 2008
Posts: 20
Country:
Thanks: 5
Thanked 0 Times in 0 Posts
Number Cruncher 20 is on a distinguished road
Default probability independent distribution
Hi,

Ive been given this question but i just can figure it out.

Suppose X,Y are Norm(1,1) and are independently and identically distributed.

Find the distribution of :

U = (X-1)/(absolute value(Y-1))

Any help would be really appreciated.
Reply With Quote