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Old November 19th, 2008, 05:40 AM
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Quote:
Originally Posted by Alienis Back View Post
factoRRRR this...and I don't know where to start

y^6-1
= (y^3)^2 - 1^2 = (y^3 - 1)(y^3 + 1) \, ....

And you should know how to factorise the sum and difference of two perfect cubes.
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