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Old November 19th, 2008, 07:08 AM
Alienis Back Alienis Back is offline
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Do you mean this??

= (y^2)^3 - 1^3

Where a=y^2 and b=1

a^3-b^3=(a-b)(a^2+ab+b^2)

Then we have...

(y^2)^3-1^3=(y^2-1) [(y^2)^2+y^2+1)]

(y^2)^3-1^3=(y^2-1) (y^4+y^2+1)

...But I don't think this is the answer...mmm...I really don't
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