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Old November 19th, 2008, 03:42 PM
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Quote:
Originally Posted by Alienis Back View Post
Do you mean this??

= (y^2)^3 - 1^3

Where a=y^2 and b=1

a^3-b^3=(a-b)(a^2+ab+b^2)

[snip]
How can you possibly think I mean that when I clearly wrote this:

Quote:
= (y^3)^2 - 1^2 = (y^3 - 1)(y^3 + 1) \, ....

And you should know how to factorise the sum and difference of two perfect cubes.
Now all you have to do is factorise each of y^3 - 1 = y^3 - 1^3 and y^3 + 1 = y^3 + 1^3.
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