Quote:
Originally Posted by brian311 Hello,
If I have a problem calling for cos(u) but elsewhere in the same problem I've calculated 3u as follows:
3u=(cos^-1(B/A)) --where B and A are symbolic constants
Is there a way of adjusting the cos(u) to accept the 3u instead so that my cos and cos^-1 will cancel out?
Thanks, |
Hey mate,
why not let 3u = t and solve for cos(t) etc, once you solve t, u is simply t/3
Hope this helps,
David