
November 21st, 2008, 02:15 PM
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Quote:
Originally Posted by davidmccormick Is it possible to partition k8 into 2 planar subgraphs? | Quote:
Originally Posted by arnaud89 I am not quite sure about that answer since you dont necesserally have 28 edges for your 2 subgraphs. | Yes you do have all 28 edges. The question says to partition into two subgraphs. I assume that is using the term partition in the standard way. |