Math Help Forum - View Single Post

David24 · #8 November 22nd, 2008, 04:46 AM

Quote:

Originally Posted by CaptainBlack

Well lets see,

$|x-2|=|x-2^{16}|$

implies (assuming $2 \le x \le 2^{16}$ anyway) that:

$x-2=2^{16}-x$

or:

$x=2^8-1$

Now lets do some calculations:

Code:

>i=1:16;
>
>x=[2^8-1:2^8+1]'
          255 
          256 
          257 
>
>s=abs(x-2^i);
>S=sum(s)
       130052 
       130050 
       130050 
>

So we conclude that, no your proposed condition does not define the solution.

CB

CaptainBlack,

Thanks for your response, I will have to keep working on it.