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Old November 23rd, 2008, 11:46 AM
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Chris L T521 Chris L T521 is offline
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Quote:
Originally Posted by ndcruz View Post
Find \mu=E(X), \sigma^2 and then \sigma

Recall that:

\mu=E(X)=\sum_{x} xP(x)

\sigma^2=E(X^2)-\left[E(X)\right]^2=\left[\sum_x xP(x) \right]-\mu^2

\sigma=\sqrt{E(X^2)-\left[E(X)\right]^2}=\sqrt{\left[\sum_x xP(x) \right]-\mu^2}

Do you think that you can solve the problem now?

--Chris
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