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Old November 25th, 2008, 01:06 AM
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1) f(x) = \left(\frac{(x^2 -1)}{\sqrt{x}}\right)^4

1: Distribute the power of 4.

f(x) = \left(\frac{(x^2 - 1)^4}{\sqrt{x}^4}\right)

2: Simplify the denominator:

f(x) = \left(\frac{(x^2 - 1)^4}{x^2}\right)

3: Use the following rule:

\frac{d}{dx}\left[\frac{u}{v}\right] = \frac{u'v - vu'}{v^2}

4: Solve:

f'(x) = \frac{8x(x^2 - 1)^3*x^2 - (x^2 - 1)^4*2x}{x^4}

5. Simplify:

f'(x) = 2x(x^2 - 1)^3\frac{4x^2 - (x^2 - 1)}{x^4}

f'(x) = 2x(x^2 - 1)^3\frac{3x^2 + 1}{x^4}
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