Thread: The Riemann Zeta Function
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Old November 28th, 2008, 03:32 AM
davidmccormick davidmccormick is offline
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But all I've done is differentiating the first term of the original series. I am pretty sure that the derivative exist and is equal to \zeta'(s) = -\sum_{r=1}^{\infty}\frac{lnr}{r^s} = -\sum_{r=2}^{\infty}\frac{lnr}{r^s}. But I have not actually shown that \zeta is differentiable.
Any thoughts.
thanks
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