Thread: Integral
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Old December 1st, 2008, 07:23 AM
Inti Inti is offline
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That integral has a little trick: the difficulty is that you have (x-2)^7, which might be difficult to integrate, so do this:
Perform the change of variables u=x-2 and you will transform your integral into \int_{-2}^{0} (u+2)u^7 du = \int_{-2}^{0} u^8+2u^7 du which is much more workable...

(I´m assuming that you wanted to get the integral between 0 and 2).
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