Thread: Very tough polynomial question.
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Old December 1st, 2008, 08:46 AM
andreas andreas is offline
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You still have that some p|b_i but p^2 \text{ doesn't divide } b_{n-1} that is some multiple of a_{n-1}.
Therefore, this h(x) is irreducible and you thus are either one or no root.

How do you prove this?
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