Thread: MAX prove question..
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Old December 2nd, 2008, 11:09 AM
Plato Plato is offline
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If A_n has no maximal term then \left( {\exists N_1 } \right)\left[ 0<{A_1 < A_{N_1 } } \right].
Moreover, \left( {K > 1} \right)\left( {\exists N_k } \right)\left[ {A_{N_{K - 1} } < A_{N_k } } \right].
That simply means that the sub sequence \left(A_{N_n}\right) cannot converge to 0.
That is a contradiction.
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