Thread: polar coordinates
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Old December 2nd, 2008, 10:05 PM
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Quote:
Originally Posted by noles2188 View Post
transform the given polar equation to rectangular coordinates

a) r = 5sec(theta) Mr F says: {\color{red}\Rightarrow r cos \theta = 5} ....

b) r = sec(theta)tan(theta) Mr F says: {\color{red}\Rightarrow r \cos \theta = \frac{\sin \theta}{\cos \theta} = \frac{y/r}{x/r} = \frac{y}{x}} ....

c) r = 4cos(theta) + 4sin(theta) Mr F says: {\color{red}\Rightarrow r = 4 \frac{x}{r} + 4 \frac{y}{r} \Rightarrow r^2 = 4x + 4y} ....
.... means the rest is left for you to finish off.
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