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Old December 3rd, 2008, 07:42 AM
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Quote:
Originally Posted by ssadi View Post
For the transformation w=z^2 show that as z moves once round the circle centre O and radius 2, w moves twice round the circle center O and radius 4.

I have two problems for which I am stuck on the sum:

1. How do moving "once" and "twice" is represented on the equation? That is, if w lies on circle center O and radius 4, |w|=4, but how do show that it moves twice?

2. If i take |z|=2, w=z^2,  z=\sqrt w, |z|=|\sqrt w|=2: how do I do this part: 2=|\sqrt w|, when w is a complex number?
And how do i carry out from there :help:
The path that you take on the circle at origin of radius two can be expressed as g(\theta) = 2e^{i\theta} for 0\leq \theta \leq 2\pi.
Under the transformation z\mapsto z^2 the path becomes mapped to \left( 2e^{i\theta} \right)^2 = 4e^{2i\theta} for 0\leq \theta \leq 2\pi. Because of the presence of 2i\theta (rather than i\theta) it means the points moves twice around a circle of radius 4.
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