Thread: Absolute minimum and maximum of a function involving e
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Old December 3rd, 2008, 01:39 PM
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The derivative of e^{x^3-x} is (3x^2 - 1)e^{x^3-x}
This is a product therefore to set the derivative equal to 0 means solving 3x²-1 = 0 (since e^anything can never be equal to 0)
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