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Old December 3rd, 2008, 07:26 PM
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Quote:
Originally Posted by ThePerfectHacker View Post
The path that you take on the circle at origin of radius two can be expressed as g(\theta) = 2e^{i\theta} for 0\leq \theta \leq 2\pi.
Under the transformation z\mapsto z^2 the path becomes mapped to \left( 2e^{i\theta} \right)^2 = 4e^{2i\theta} for 0\leq \theta \leq 2\pi. Because of the presence of 2i\theta (rather than i\theta) it means the points moves twice around a circle of radius 4.
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