Thread: Well these are a teaser too..Trigonometry
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Old December 4th, 2008, 10:02 AM
Soroban Soroban is offline
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Hello, Sinsane!

You're expected to know the trig values for certain angles.

. . For example: .\sin30^o \:=\:\tfrac{1}{2} . . . and its variations.

If you dont, sayonara . . .


Quote:
Solve the equation for solutions in the interval [0°, 360°).

\sin2\theta \:=\: \text{-}\tfrac{1}{2}

This gives us: .2\theta \:=\:210^o,\:330^o,\:570^o,\:690^o,\:\hdots

Therefore: .\theta \;=\;105^o,\:165^o,\:285^o,\:345^o



Quote:
\sqrt{3} \sec2\theta \:=\: 2

So we have: .\sec2\theta\;=\;\frac{2}{\sqrt{3}}

Hence: .2\theta \;=\;30^o,\:150^o,\:389^o,\:510^o,\: \hdots

Therefore: .\theta \;=\;15^o,\:75^o,\:195^o,\:255^o
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